Great introductory post – thanks a lot!

I think I know exactly how you feel! My archive is so overly full of indicators that I coded or enhanced I can hardly count them.

In this general wording, I believe that your statement is wrong. I would prefer to state a little more carefully:

For two given timeframes TF0 and TF1, where TF1 = N * TF0 and N > 1, price is h0-recurrent in TF0 if price is h1-recurrent in TF1 and h0 = N * h1.

Hmm – correct? Still thinking …

For h1-intervals other than h1 = N *…[Read more]

In this general wording, I believe that your statement is wrong. I would prefer to state a little more carefully:

For two given timeframes TF0 and TF1, where TF1 = N * TF0 and N > 1, price is h0-recurrent in TF0 if price is h1-recurrent in TF1 and h1 = N * h0.

Hmm – correct? Still thinking …

For h1-intervals other than h1 = N *…[Read more]

I’m not sure I understand what you mean by fake TZ. Maybe PTZ that will not be confirmed?

I also thought about an MTF approach. Anyway I’m sure (without having a mathematical proof, though) that we may not assume that TZ events analyzed at one point in time (realtime) in different timeframes are statistically independent of each other. Thus…[Read more]

I like this puzzle, thanks bro

Happy New Year every body ….
This is great Zelo. Do you have a plan to include probability calculation ?   Check probability at bigger TF, and also at smaller TF would be nice in my opinion bro 

Thank you, aryafx, for pointing me back to your older post!

You are absolutely right: I too believe that TZ on the same symbol, observed in different timeframes, are by no means independent of each other. So we may conclude that it would be simply incorrect to calculate some compound TZ related probability on different timeframes at the very…[Read more]

I even thought it could make sense to go down to the very extreme: h = 1.

Very clear chart pic and evaluation! Thanks a lot!

My current analysis is showing in exactly the same direction. Didn’t have enough time yet to work it out in sound statistics.

Simple testing.

IMO, absolutely NO! You’re having 3 independent events if you’re drawing lottery tickets out of 3 buckets independently. If winning probabilities of those single events are P0, P1, and P2, then the compound probability for all drawings to be successful is P = P0 * P1 * P2.

But I definitely doubt that 3 events taking place on the very same bar…[Read more]

Yes, that’s correct!

Hi G, do you mean the red yellow arrows ?

Thank you bro Kiads for you “New Year” gift

Agree! This is just because those single events like PTZ / CTZ are not independent of each other within one chart. If they were independent of each other, we could find a compound probability simply by multiplying all single probabilities.

If we do not find a mathematically formal description of the correlation between those single events…[Read more]